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#reading-9-probability-concepts
Question

For any number of independent events E1, E2.....En, the probability that all of them occur is:

P(E1 and E2..... and En) = [...]
Answer
P(E1) x P(E2) x ..... x P(En)

Tags
#reading-9-probability-concepts
Question

For any number of independent events E1, E2.....En, the probability that all of them occur is:

P(E1 and E2..... and En) = [...]
Answer
?

Tags
#reading-9-probability-concepts
Question

For any number of independent events E1, E2.....En, the probability that all of them occur is:

P(E1 and E2..... and En) = [...]
Answer
P(E1) x P(E2) x ..... x P(En)
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Subject 4. Multiplication Rule for Independent Events
in the deck, the probability of the first event is 1/52. Since 13/52 = 1/4 of the deck is composed of clubs, the probability of the second event is 1/4. Therefore, the probability of both events is: 1/52 x 1/4 = 1/208. Similarly, <span>for any number of independent events E 1 , E 2 .....E n , the probability that all of them occur is: P(E 1 and E 2 ..... and E n ) = P(E 1 ) x P(E 2 ) x ..... x P(E n ) Example In a bullish market, three shares, chosen from different sectors of the market, have probabilities of 0.6, 0.5 and 0.8 that their share prices will ris

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